Integrand size = 24, antiderivative size = 102 \[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{x^2} \, dx=\frac {b e m n \log (x)}{d}-\frac {b e n \log \left (1+\frac {d}{e x}\right ) \log \left (f x^m\right )}{d}-\frac {b e m n \log (d+e x)}{d}-\left (\frac {m}{x}+\frac {\log \left (f x^m\right )}{x}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )+\frac {b e m n \operatorname {PolyLog}\left (2,-\frac {d}{e x}\right )}{d} \]
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Time = 0.05 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2473, 2379, 2438, 36, 29, 31} \[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{x^2} \, dx=-\left (\frac {\log \left (f x^m\right )}{x}+\frac {m}{x}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )-\frac {b e n \log \left (\frac {d}{e x}+1\right ) \log \left (f x^m\right )}{d}+\frac {b e m n \operatorname {PolyLog}\left (2,-\frac {d}{e x}\right )}{d}+\frac {b e m n \log (x)}{d}-\frac {b e m n \log (d+e x)}{d} \]
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Rule 29
Rule 31
Rule 36
Rule 2379
Rule 2438
Rule 2473
Rubi steps \begin{align*} \text {integral}& = -\left (\left (\frac {m}{x}+\frac {\log \left (f x^m\right )}{x}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )\right )+(b e n) \int \frac {\log \left (f x^m\right )}{x (d+e x)} \, dx+(b e m n) \int \frac {1}{x (d+e x)} \, dx \\ & = -\frac {b e n \log \left (1+\frac {d}{e x}\right ) \log \left (f x^m\right )}{d}-\left (\frac {m}{x}+\frac {\log \left (f x^m\right )}{x}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )+\frac {(b e m n) \int \frac {1}{x} \, dx}{d}+\frac {(b e m n) \int \frac {\log \left (1+\frac {d}{e x}\right )}{x} \, dx}{d}-\frac {\left (b e^2 m n\right ) \int \frac {1}{d+e x} \, dx}{d} \\ & = \frac {b e m n \log (x)}{d}-\frac {b e n \log \left (1+\frac {d}{e x}\right ) \log \left (f x^m\right )}{d}-\frac {b e m n \log (d+e x)}{d}-\left (\frac {m}{x}+\frac {\log \left (f x^m\right )}{x}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )+\frac {b e m n \text {Li}_2\left (-\frac {d}{e x}\right )}{d} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.09 \[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{x^2} \, dx=-\frac {b e m n x \log ^2(x)+2 \left (m+\log \left (f x^m\right )\right ) \left (a d+b e n x \log (d+e x)+b d \log \left (c (d+e x)^n\right )\right )-2 b e n x \log (x) \left (m+\log \left (f x^m\right )+m \log (d+e x)-m \log \left (1+\frac {e x}{d}\right )\right )+2 b e m n x \operatorname {PolyLog}\left (2,-\frac {e x}{d}\right )}{2 d x} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 5.36 (sec) , antiderivative size = 709, normalized size of antiderivative = 6.95
method | result | size |
risch | \(\left (-\frac {b \ln \left (x^{m}\right )}{x}-\frac {-i \pi b \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )+i \pi b \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}+i \pi b \,\operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}-i \pi b \operatorname {csgn}\left (i f \,x^{m}\right )^{3}+2 b \ln \left (f \right )+2 b m}{2 x}\right ) \ln \left (\left (e x +d \right )^{n}\right )+\left (-\frac {i b \pi \,\operatorname {csgn}\left (i c \left (e x +d \right )^{n}\right ) \operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i \left (e x +d \right )^{n}\right )}{4}+\frac {i \pi \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2} b}{4}+\frac {i \pi \,\operatorname {csgn}\left (i \left (e x +d \right )^{n}\right ) \operatorname {csgn}\left (i c \left (e x +d \right )^{n}\right )^{2} b}{4}-\frac {i \pi \operatorname {csgn}\left (i c \left (e x +d \right )^{n}\right )^{3} b}{4}+\frac {b \ln \left (c \right )}{2}+\frac {a}{2}\right ) \left (-\frac {-i \pi \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )+i \pi \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}+i \pi \,\operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}-i \pi \operatorname {csgn}\left (i f \,x^{m}\right )^{3}+2 \ln \left (f \right )}{x}-\frac {2 \ln \left (x^{m}\right )}{x}-\frac {2 m}{x}\right )-\frac {e n b \ln \left (x^{m}\right ) \ln \left (e x +d \right )}{d}+\frac {e n b \ln \left (x^{m}\right ) \ln \left (x \right )}{d}-\frac {e n b m \ln \left (x \right )^{2}}{2 d}+\frac {e n b m \ln \left (e x +d \right ) \ln \left (-\frac {e x}{d}\right )}{d}+\frac {e n b m \operatorname {dilog}\left (-\frac {e x}{d}\right )}{d}-\frac {i e n b \ln \left (e x +d \right ) \pi \,\operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}}{2 d}-\frac {i e n b \ln \left (x \right ) \pi \operatorname {csgn}\left (i f \,x^{m}\right )^{3}}{2 d}-\frac {i e n b \ln \left (e x +d \right ) \pi \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}}{2 d}-\frac {i e n b \ln \left (x \right ) \pi \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )}{2 d}-\frac {e n b \ln \left (e x +d \right ) \ln \left (f \right )}{d}-\frac {b e m n \ln \left (e x +d \right )}{d}+\frac {i e n b \ln \left (e x +d \right ) \pi \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )}{2 d}+\frac {i e n b \ln \left (x \right ) \pi \,\operatorname {csgn}\left (i f \right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}}{2 d}+\frac {i e n b \ln \left (e x +d \right ) \pi \operatorname {csgn}\left (i f \,x^{m}\right )^{3}}{2 d}+\frac {i e n b \ln \left (x \right ) \pi \,\operatorname {csgn}\left (i x^{m}\right ) \operatorname {csgn}\left (i f \,x^{m}\right )^{2}}{2 d}+\frac {e n b \ln \left (x \right ) \ln \left (f \right )}{d}+\frac {b e m n \ln \left (x \right )}{d}\) | \(709\) |
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\[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{x^2} \, dx=\int { \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} \log \left (f x^{m}\right )}{x^{2}} \,d x } \]
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Timed out. \[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{x^2} \, dx=\text {Timed out} \]
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Time = 0.25 (sec) , antiderivative size = 162, normalized size of antiderivative = 1.59 \[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{x^2} \, dx=-\frac {1}{2} \, {\left (\frac {2 \, {\left (\log \left (\frac {e x}{d} + 1\right ) \log \left (x\right ) + {\rm Li}_2\left (-\frac {e x}{d}\right )\right )} b e n}{d} + \frac {2 \, b e n \log \left (e x + d\right )}{d} - \frac {2 \, b e n x \log \left (e x + d\right ) \log \left (x\right ) - b e n x \log \left (x\right )^{2} + 2 \, b e n x \log \left (x\right ) - 2 \, b d \log \left ({\left (e x + d\right )}^{n}\right ) - 2 \, b d \log \left (c\right ) - 2 \, a d}{d x}\right )} m - {\left (b e n {\left (\frac {\log \left (e x + d\right )}{d} - \frac {\log \left (x\right )}{d}\right )} + \frac {b \log \left ({\left (e x + d\right )}^{n} c\right )}{x} + \frac {a}{x}\right )} \log \left (f x^{m}\right ) \]
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\[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{x^2} \, dx=\int { \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )} \log \left (f x^{m}\right )}{x^{2}} \,d x } \]
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Timed out. \[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{x^2} \, dx=\int \frac {\ln \left (f\,x^m\right )\,\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )}{x^2} \,d x \]
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